1.

What is the freezing point of a solution containing 8.1 g HBr in 100g water assuming the acid to be 90% ionised (K_(f) for water = 1.86 "Kg mole"^(-1))

Answer»

`0.85^(@)C`
`-3.53^(@)C`
`0^(@)C`
`-0.35^(@)C`

Solution :`{:(HBR,hArr,H^(+),+,Br^(-)),((1-ALPHA),,alpha,,alpha):}`
Total `= 1+alpha THEREFORE i=1+alpha=1+0.9=1.9`
`DELTA T_(f)= i K_(f)xx m=1.9xx1.86xx(8.1)/(81)xx(1000)/(100)=3.53^(@)C`
`T_(f)=-3.53^(@)C`.


Discussion

No Comment Found

Related InterviewSolutions