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What is the frequency and energy of a photon of wavelength 6000 A^@ (Given h = 6.6 xx 10^(-34) Js, C = 3 xx 10^8 ms^(-1)). |
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Answer» Solution :FREQUENCY V = `c/ lambda = (3 xx 10^8)/(6000 xx 10^(-10)) = 5 xx 10^14 Hz` and energy = hv=`6.6 xx 10^-34 xx 5 xx 10^14 = 3.3 xx 10^-19 J` |
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