1.

What is the [H^(+)] in a 0.40 M solution of HOCl, K_(a)=3.5xx10^(-8)?

Answer»

`1.4xx10^(-8)M`
`1.2xx10^(-4)M`
`1.9xx10^(-4)M`
`3.7xx10^(-4)M`

Solution :`[H^(+)]=sqrt(K_(a)XXC)`
`=sqrt(3.5xx10^(-8)xx0.4)`
`=sqrt(140xx10^(-10))`
`=12XX10^(-5)`
`=1.2xx10^(-4)`


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