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What Is The Least Number That Must Be Subtracted 2458 So That It Becomes Completely Divisible By 13? |
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Answer» DIVIDE 2458 by 13 and we GET REMAINDER as 1. Then 131=12. Adding 12 to 2458 we get 2470 which is divisible by 13. Thus ANSWER is 1. Divide 2458 by 13 and we get remainder as 1. Then 131=12. Adding 12 to 2458 we get 2470 which is divisible by 13. Thus answer is 1. |
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