1.

What Is The Least Number That Must Be Subtracted 2458 So That It Becomes Completely Divisible By 13?

Answer»

DIVIDE 2458 by 13 and we GET REMAINDER as 1.

Then 131=12.

Adding 12 to 2458 we get 2470 which is divisible by 13.

Thus ANSWER is 1.

Divide 2458 by 13 and we get remainder as 1.

Then 131=12.

Adding 12 to 2458 we get 2470 which is divisible by 13.

Thus answer is 1.



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