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What is the magnanitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of 30^(@) with the direction of a uniform magnetic field of 0.15 T ? |
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Answer» Solution :I =8A, `THETA = 30^@`, B = 0.15 T `F= Bl // sin theta` `F/l = BI sin theta = 0.15 xx 8 xx sin 30 = 0.6 Nm^(-1)` |
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