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What is the magnitude of the equatorial and axial fields due to a bar magnet of length 5.0 cm at a distance of 50 cm from its mid-point? The magnetic moment of the bar magnet is 0.40 A m^2, the same as in Example 5.2. |
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Answer» SOLUTION :From Eq (5.7) `B_(E)=(mu_(0)m)/(4pi r^(2))=(10^(-7) XX 0.4)/((0.5)^(3))=(10^(-7) xx 0.4)/(0.125) =3.2 xx 10^(-7)T` From Eq. (5.8) `B_(A)=(mu_(0)2m)/(4pi r^(3))=6.4 xx 10^(-7)T` |
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