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What is the magnitude of the equatorial and axial fields dut to a bar magnet of length 5.0 cm at a distance of 50 cm from its mid - point ? The magnetic moment of the bar magnet is 0.40Am^2 .

Answer»

SOLUTION :`B_E=(mu_0m)/(4pir^3)=(10^(-7)xx0.4)/((0.5)^3)=(10^(-7)xx0.4)/(0.125)=3.2xx10^(-7)T`
`B_A=(mu_02m)/(4pir^2)=6.4xx10^(-7)T`


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