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What is the magnitude of voltage generated at emitter circuit of a CE short circuit current frequency response model?(a) hre × hfe / Ib × RL(b) hre × hfe × Ib × RL(c) hre × hfe / IC × RL(d) hre × hfe × IC × RLThe question was posed to me in an internship interview.My question is from The CE Short Circuit Current Frequency Response in section High Frequency Transistor of Electronic Devices & Circuits

Answer»

Right choice is (b) hre × hfe × Ib × RL

The explanation: The magnitude of voltage generated at emitter CIRCUIT of a common emitter (CE) amplifier can be expressed in terms of hybrid parameters in the CE short circuit CURRENT frequency response model. The magnitude of voltage generated is equal to hre × hfe × Ib × RL where, RL is LOAD resistance and Ib is the BASE current.



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