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What is the mass (in grams) of an aluminium block whose dimensions are "2.0 in."xx"3.0 in."xx"4.0 in." and whose density is 2.7g//cm^(3)? Given that 1 in. = 2.54 cm. |
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Answer» Solution :Here, unit CONVERSION FACTORS are `1=(2.54cm)/("1 in.")=("1 in")/(2.54cm)` Hence, required mass (in g) `= "2.0 in"XX"3.0 in"xx"4.0 in"xx(2.54cm)/("1 in")xx(2.54cm)/("1 in")xx(2.54cm)/("1 in")xx(2.7g)/(1cm^(3))=1.1xx10^(3)g.` |
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