1.

What is the mass of 1 curie of ""_(27)C^(60) ? Half life of ""_(27)C^(60) is 5.25 years:

Answer»

`8.8 xx 10^(-6)kg`
`8.8 xx 10^(-7)kg`
`8.8 xx 10^(-8)kg`
`8.8 xx 10^(-9)kg`

Solution :`R=(d N)/(dt) =lambda N =3.7 xx 10^(10) //SEC`.
`N=(3.7 xx 10^(10))/(lambda)=(3.7 xx 10^(10) xx T)/(0.693)`
`=(3.7 xx 10^(10) xx 5.25 xx 3.16 xx 10^(7))/(0.693)`
`=8.85 xx 10^(18)`
Mass of N atoms `=(60 xx 8.85 xx 10^(18))/(6.02 xx 10^(26)) kg`
`=8.8 xx 10^(-7)kg`


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