1.

What is the maximum and minimum possible resistance which can be determined using the PO Box shown in above .

Answer»

<P>`1111 kOmega, 0.1Omega`
`1111 kOmega, 0.01Omega`
`1111 kOmega, 0.001Omega`
NONE of these

Solution :`X=(Q)/(P)RrArr(X)_(max)=((Q)_(max))/((P)_(max))(R)_(max)=(1000)/(10)(11110)=1111kOmega`
`(X)_(min)=((Q)_(min))/((P)_(max))( R)_(min)=(10)/(1000)(10)/(10000)(1)=0.01Omega` .


Discussion

No Comment Found

Related InterviewSolutions