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What is the maximum height of a stone thrown vertically upwards if its velocity is halved in 2 second ? |
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Answer» 20 m `h=(u^(2))/(2G)` ALSO v=u+at `u/2=u-gxx2` =`u-10xx2` or u=40 `MS^(-1)` `:. H=(40xx40)/(2XX10)=80 m` |
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