1.

What is the maximum height of a stone thrown vertically upwards if its velocity is halved in 2 second ?

Answer»

20 m
40 m
80 m
100 m

Solution :Here let .h.be the max height and u be the velocityof thrown,then
`h=(u^(2))/(2G)`
ALSO v=u+at
`u/2=u-gxx2`
=`u-10xx2`
or u=40 `MS^(-1)`
`:. H=(40xx40)/(2XX10)=80 m`


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