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What is the maximum value of force F such that the block shown in does not move ? |
Answer» The body diagram of the block is shown in Clearly `R = mg + F sin 60^(@)` The block will not move , when `F cos 60^(@) le f` (force of friction) `(F)/(2) le mu R ` `(F)/(2) le mu (mg + F sin 60^(@))` `(F)/(2) le (1)/(2 sqrt(3))(sqrt3g + F sqrt3/2)` `(F)/(2) le ((g)/(2) + (F)/(4))` or `(F)/(2) - (F)/(4) le(g)/(2)` or `F//4 le (g)/(2)` `F le 2 g` Hence `F_(max) = 2 g = 2 xx 10 = 20 N` |
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