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    				| 1. | What is the middle term in the expansion of `(1-(x)/(2))^(8)` ?A. `(35x^(4))/(8)`B. `(17x^(5))/(8)`C. `(35x^(5))/(8)`D. None of these | 
| Answer» Correct Answer - A Since n = 8 is even number therefore middle term `=((n)/(2)+1)^(th)"term"=(4+1)=5^(th)"term"` Hence, `T_(5)=.^(8)C_(4)(1)^(4)(-(x)/(2))^(4)` `=(8!)/(4!4!)xx(x^(4))/(16)=(8xx7xx6xx5)/(4xx3xx2xx1).(x^(4))/(16)=(70x^(4))/(16)=(35x^(4))/(8)` | |