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What is the minimum energy released in the annhilation of an electron positron pair? |
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Answer» The rest mass of an electron or positron is `m_(0)=9.1xx10^(-31)kg.` In the annhilation of an electron positron pair, the rest mass of the two particles is converted into energy. `:.` Minimum energy released, `E=2m_(0)c^(2)=2(9.1xx10^(-31))(3xx10^(8))^(2)jou l e`. ` E=(2xx9.1xx9xx10^(-15))/(1.602xx10^(-13))MeV=1.02MeV` |
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