1.

What is the mole fraction of the solute in a 1.00 m aqueous solution ?

Answer»

`0.0354`
`0.0177`
`0.177`
`1.770`

Solution :1.00 m solution means 1 MOLE solute is present in 1000 G water.
`n_(H_(2)O)=(1000)/(18)=55.5 mol H_(2)O`
`X_("solute")=(n_("solute"))/(n_("solute")+n_(H_(2)O))=(1)/(1+55.5)=0.0177`


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