1.

What is the moment of inertia and K.E. of a thin uniform ring of mass 2 kg and diameter 1 m rotating about the axis passing through its centre and perpendicular to the plane of the ring?

Answer»

`0.5kgm^(2)`
`1.0kgm^(2)`
`2.0kgm^(2)`
`4.0kgm^(2)`

SOLUTION :`I=mr^(2)`
`I=2xx((1)/(2))^(2)=0.5kgm^(2)`


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