1.

What is the normality of a solution that results from mixing 7.4 g of `Ca(OH)_2, 500` " mL of " `1 M HNO_3` and `10.0 mL` of `H_2SO_4` (specific gravity`=1.2,49%H_2SO_4` by weight)? The total volume of the solution was made to 1L after adding water?

Answer» (a). `Mw[Ca(OH)_2]=40+34=74`
`7.4g. Of Ca (OH)_2=(7.4)/(74)-=0.1mol=10m` moles
`=10xx2mEq` (n-factor`=2)`
`-=20mEq`
(b). `500 " mL of " 1 M HNO_3=500xx1xx1` (n-factor)
`-=20mEq`
(b). `500 " mL of " 1 M HNO_3=00xx1xx1` (n-factor)
`-=500 mEq`
(c). Normality of `H_2SO_4`
`=(Wxx1000)/(Ewxx"Volume of solution in mL")`
`{:[(Mw=98,"n-factor=2),(Ew=(98)/(2)=49g)]:}`
or Normality of `H_2SO_4`
`=(%"by weight"xx"density"("or specific gravity"))/(Ew)`
`=(49xx10xx1.2)/(49)=12N`
`m" Eq of "H_2SO_4=NxxV=12xx10=120 mEq`
(d). Total m" Eq of "acid `=500+120=620 mEq`
(e). m" Eq of "`Ca(OH_2)=20mEq`
(f). m" Eq of "acid left `=620-20=600 mEq`
(g). Normality of solution `=(mEq)/(V(mL))=(600)/(1000)=0.6N`


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