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What is the number of electrons transferred in an equation if the Nernst equation is E(cell) = E°(cell) – 9.83 × 10^-3 × log10 (Anode / Cathode)?(a) 2(b) 6(c) 4(d) 1I have been asked this question in my homework.My question is taken from Electrochemistry in division Electrochemistry of Chemistry – Class 12

Answer»

The CORRECT choice is (b) 6

Explanation: Nernst EQUATION = E°(cell) – \(\FRAC{0.059}{n}\) log10(Anode / Cathode)

On comparing both the FORMULAE,\(\frac{0.059}{n}\) = 9.83 × 10^-3

n= 6.



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