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What is the number of unpaired electrons in [Fe(H2O)6]^2+ if it is known to be a high spin complex?(a) 0(b) 2(c) 3(d) 4I got this question during an interview.Origin of the question is Bonding in Coordination Compounds topic in division Coordination Compounds of Chemistry – Class 12

Answer»

Correct choice is (d) 4

The EXPLANATION: The configuration of Fe^2+ is 3d^6. The complex has a CN=6 has should have sp^3d^2 hybridisation. This leaves the 3d ORBITALS as it is with 4 UNPAIRED ELECTRONS.



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