What is the osomotic pressure of a "0.0020 mol dm"^(-3) sucrose (C_(12 – InterviewSolution

1.	What is the osomotic pressure of a "0.0020 mol dm"^(-3) sucrose (C_(12)H_(22)O_(11)) solution at 20^(@)C? (Molar gas constant, R ="8.314 JK"^(-1)"mol"^(-1))
Answer» 4870 Pa 4.87 Pa 0.00487 Pa 0.33 Pa Solution :`pi-CRT` `C="0.002 MOL DM"^(-3)="2 mol m"^(-3)` `R=8.314JK^(-1)"mol"^(-1),T=293K` `pi=2xx8.314xx293=4872Pa`.

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