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What is the overall length of fillet weld to be provided for lap joint to transmit a factored load of 100kN? Assume site welds and width and thickness of plate as 75mm and 8mm respectively, Fe410 steel.(a) 500mm(b) 382mm(c) 201mm(d) 468mmThe question was posed to me during an interview.My enquiry is from Design of Welds in section Welded Connections of Design of Steel Structures |
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Answer» CORRECT answer is (c) 201MM For EXPLANATION I would say: Minimum size of weld = 3mm Maximum size of weld = 8-1.5 = 6.5mm Assume size of weld = 5mm Effective throat thickness = 0.7 X 5 = 3.5mm Strength of weld = 3.5×410/(√3 x1.5) = 552.33 N/mm Required length of weld = 100 x 10^3/552.33 = 181.05 mm length to be provided on each side = 181/2 = 90.5mm End return = 2×5 = 10mm Overall length = 2 x (90.5 + 2 x 5) = 201mm. |
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