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What is the perpendicular distance between the parallel lines `3x+4y=9` and `9x+12 y+28=0` ?A. `7/3` unitsB. `8/3` unitsC. `10/3` unitsD. `11/3` units |
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Answer» Correct Answer - D The given lines are :- `3x+4y=9` `implies y=9/4-3/4 x` ...(i) and `9x+12y+28=0 implies y= (-7)/3-(3x)/4` ...(ii) We have, `m=(-3)/4, C_(1)=9/4, C_(2)=(-7)/3` Now, Distance `=(|C_(1)-C_(2)|)/sqrt(1+m^(2))=(|9/4-(-7/3)|)/sqrt(1+9/16)=11/3` units |
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