1.

What is the phase difference between two simple harmonic motions represented by x_(1) = A sin(omega t + pi/6) and x_(2) = A cos (omegat)?

Answer»

`pi//6`
`pi//3`
`pi//2`
`2pi//3`

Solution :`x_(1) = A sin(OMEGA t + pi/6)`
`x_(2) =A cos omega t = A sin (omega t + pi/2)`
PHASE difference, `DELTAPHI - phi_(2) - phi_(1)`
`=(OMEGAT + pi/2) -(omega t+ pi/6) = pi/3`


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