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What is the potential difference between 10sinθcosφ/r^2 at A(1,30,20) and B(4,90,60)?(a) 2.386(b) 3.386(c) 4.386(d) 5.386The question was asked during a job interview.Origin of the question is Electric Potential in chapter Electrostatic Fields of Electromagnetic Theory |
Answer» CORRECT answer is (c) 4.386 The explanation is: POTENTIAL at A, Va = 10sin30cos20/1^2 = 4.6985 and Potential at B, VB = 10sin90cos60/4^2 = 0.3125. Potential DIFFERENCE between A and B is, Vab = 4.6985 – 0.3125 = 4.386 volts. |
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