1.

What is the probability of obtaining 4 heads in a row when a coin is tossed?(a) \(\frac {5}{8}\)(b) \(\frac {6}{19}\)(c) \(\frac {1}{16}\)(d) \(\frac {4}{7}\)I got this question during a job interview.I'd like to ask this question from Probability topic in portion Probability of Mathematics – Class 12

Answer»

The correct option is (c) \(\FRAC {1}{16}\)

EASIEST explanation: Probability of getting 4 heads in a row = \(\frac {1}{2} \times \frac {1}{2} \times \frac {1}{2} \times \frac {1}{2} = \frac {1}{16}\)

HENCE, the probability of getting 4 heads in a row = \(\frac {1}{16}\)



Discussion

No Comment Found

Related InterviewSolutions