What is the probability that a given two-digit number is divisible by

1.	What is the probability that a given two-digit number is divisible by 15?
Answer» No. of two digits number = 90 ⇒ n(S) = 90. Let ‘A’ be the event of getting a number divisible by 15. ⇒ A = {15, 30, 45, 60, 75, 90} ⇒ n(A) = 6 ∴ p(A) = \(\frac{n(A)}{n(S)}\) = \(\frac{6}{90}\) = \(\frac{1}{15}\) ∴ The probability of getting a number divisible by 15 = \(\frac{1}{15}\) .

What is the probability that a given two-digit number is divisible by 15?

Answer»

No. of two digits number = 90

⇒ n(S) = 90.

Let ‘A’ be the event of getting a number divisible by 15.

⇒ A = {15, 30, 45, 60, 75, 90}

⇒ n(A) = 6

∴ p(A) = \(\frac{n(A)}{n(S)}\) = \(\frac{6}{90}\) = \(\frac{1}{15}\)

∴ The probability of getting a number divisible by 15 = \(\frac{1}{15}\) .

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What is the probability that a given two-digit number is divisible by 15?

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