What is the probability that a leap year has 53 Tuesdays and 53 Monday

1.	What is the probability that a leap year has 53 Tuesdays and 53 Mondays?
Answer» A leap year has 366 days (52 weeks + 2 days) That two days may be (sun, mon) (mon, tue) (tue, wed) (wed, thurs) (thurs, fri) (fri, sat) (sat, sun) ∴ n(S) = 7 Number of events for the occurrence of 53 Tuesdays and 53 Mondays, n(E) = 1 ∴ \(\frac{n(E)}{n(S)}\) = \(\frac{1}{7}\)

What is the probability that a leap year has 53 Tuesdays and 53 Mondays?

Answer»

A leap year has 366 days (52 weeks + 2 days)

That two days may be (sun, mon) (mon, tue) (tue, wed) (wed, thurs) (thurs, fri) (fri, sat) (sat, sun)

∴ n(S) = 7

Number of events for the occurrence of 53 Tuesdays and 53 Mondays, n(E) = 1

∴ \(\frac{n(E)}{n(S)}\) = \(\frac{1}{7}\)

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What is the probability that a leap year has 53 Tuesdays and 53 Mondays?

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