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What is the probability that a randomly chosen two-digit positive integer is a multiple of 3. |
Answer» Let n(s) = 90 A = {12,15 ……………… 99} n(A) = 30 P(A) = \(\frac{n(A)}{n(S)}\) = \(\frac{30}{90}\) = \(\frac{1}{3}\) Using a + (n — 1)d = Tn 12+ (n – 1)3 = 99 12 + 3x – 3 = 99 3x = 99 – 9 3x = 90; x = 30 |
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