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What is the probability that an ordinary year has 53 Sundays? |
Answer» Ordinary year has 365 days 365 days = 52 weeks + 1 day That 1 day may be Sun, Mon, Tue, Wed, Thu, Fri, Sat Total no. of possible outcomes = 7 Let E ⟶ event of getting 53 Sundays No. of favourable outcomes = 1 {Sun} P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes) = 1/7 |
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