What is the probability that an ordinary year has 53 Tuesdays?

1.	What is the probability that an ordinary year has 53 Tuesdays?
Answer» We know that, Probability of occurrence of an event = \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\) An ordinary year has 365 days i.e. it has 52 weeks + 1 day. So, there will be 52 Tuesdays for sure(because every week has 1 Tuesday) So, we want another Tuesday that to from that 1 day left(as there is only one Tuesday left after 52 weeks) This one day can be, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Of these total 7 outcomes, the desired outcome is 1, i.e. Tuesday Therefore, the probability of getting 52 Tuesdays in an ordinary year = \(\frac{1}{7}\) Conclusion: Probability of getting 53 Tuesdays in an ordinary year is \(\frac{1}{7}\)

Answer»

We know that,

Probability of occurrence of an event

= \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\)

An ordinary year has 365 days i.e. it has 52 weeks + 1 day. So, there will be 52 Tuesdays for sure(because every week has 1 Tuesday)

So, we want another Tuesday that to from that 1 day left(as there is only one Tuesday left after 52 weeks)

This one day can be, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Of these total 7 outcomes, the desired outcome is 1, i.e. Tuesday

Therefore, the probability of getting 52 Tuesdays in an ordinary year = \(\frac{1}{7}\)

Conclusion: Probability of getting 53 Tuesdays in an ordinary year is \(\frac{1}{7}\)

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