1.

What is the probability that the 2 students have the same birthday?

Answer»

Let P(E) = The probability that two students not having the same birthday = 0.992 

Then P(\(\overline{E}\)) = The complementary event of E, i.e., two students having the same birthday 

Also, P(E) + p(\(\overline{E}\)) = 1 

∴ The probability that two students have the same birthday P(\(\overline{E}\)) = 1 – P(E) 

= 1 – 0.992 = 0.008



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