1.

What is the rate law for the reaction. NO_(2_((g)))+CO_((g)) to NO_((g))+CO_(2_((g))) The reaction occurs in the following steps: (i) NO_(2)+NO_(2) to NO_(3)+NO("slow") (ii) NO_(3)+CO to NO_(2)+CO_(2)("fast") What is the role of NO_(3)?

Answer»

Solution :Overall REACTION:
`NO_(2_((g)))+CO_((g)) to NO_((g))+CO_(2_((g)))`
`"Step-I" NO_(2)+NO_(2) to NO_(3)+NO("SLOW")`
`"Step-II" NO_(3)+CO to NO_(2)+CO("fast")`
(A) From first RATE DETERMINING slow step, rate law is, Rate =`k[NO_(2)]^(2)`
Role of `NO_(3)` : In the reaction, `NO_(3)` is the reaction intermediate which is FORMED in first step and removed in the second step.


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