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What is the ratio of Bohr magneton to the nuclear magneton?

Answer»

`(m_(p))/(m_(E))`
`(m_(p)^(2))/(m_(e)^(2))`
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`(m_(e))/(m_(p))`

Solution :Bohr magneton,` mu_(B) = (eh)/(2m_(e))`
NUCLEAR magneton, `mu_(N) = (eh)/(2m_(p))``therefore (mu_(B))/(mu_(N)) = (m_(p))/(m_(e))`


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