1.

What is the ratio of circumference of 3"d orbit of He" and 5th orbit of Hydrogen(A) 3:5(C) 9:50(D) of these

Answer»

R = 0.529n²/z

for He 3rd orbit R = 0.529*(3)²/2

for H 5th orbit R = 0.529*(5)²/1

so ratio of circumference He/H = 2π(0.529)9/2/2π(0.529)*(25) = 9/2*25 = 9/50

option C


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