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What is the refractive index of water ? |
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Answer» Solution :` A = 60^(@) , D_(m) = 40^(@)` n ` = (SIN ((A + D_(m))/(2)) )/( sin((A)/(2))) = (sin ""((60 + 40)/(2)))/( sin((60)/(2))) = 1.53 "" n_(gw) = (n_(g))/(n_(w)) = (1.53)/(1.53) = 1.15` `n_(gw) = (sin ((A + D_(m))/(2)) )/( sin((A)/(2)))"" i.e., 1.15 = (sin"" ((60 + D_(m))/(2)))/( sin 30 )` `therefore sin ((60 + D_(m))/(2)) = 1.15 xx sin 30 = 0.573 ` ` (60 + D_(m))/(2)= 35^(@) 6.` `D_(m) = 70^(@) 12. - 60^(@) = 10^(@) 12.` |
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