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What is the relation between current and voltage in a capacitor?(a) I=1/C*integral(Vdt)(b) I=CdV/dt(c) I=1/CdV/dt(d) I=CtThis question was posed to me in my homework.This interesting question is from Capacitors topic in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Correct ANSWER is (b) I=CdV/dt

For EXPLANATION: Current=rate of CHANGE of charge

I=dQ/dt. Q=CV. C(CAPACITANCE) is constant for a given capacitor so I=CdV/dt.



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