What is the relation between h(t) and Ha(s)?(a) Ha(s)=\( \int_{-\infty}^{\infty} h(t)e^{-st} dt\)(b) Ha(s)=\(\int_0^{\infty} h(t)e^{st} dt\)(c) Ha(s)=\( \int_{-\infty}^{\infty} h(t)e^{st} dt\)(d) None of the mentionedThis question was addressed to me in an interview for internship.The doubt is from Design of IIR Filters from Analog Filters in division Digital Filters Design of Digital Signal Processing

What is the relation between h(t) and Ha(s)?(a) Ha(s)=\( \int_{-\infty

1.	What is the relation between h(t) and Ha(s)?(a) Ha(s)=\( \int_{-\infty}^{\infty} h(t)e^{-st} dt\)(b) Ha(s)=\(\int_0^{\infty} h(t)e^{st} dt\)(c) Ha(s)=\( \int_{-\infty}^{\infty} h(t)e^{st} dt\)(d) None of the mentionedThis question was addressed to me in an interview for internship.The doubt is from Design of IIR Filters from Analog Filters in division Digital Filters Design of Digital Signal Processing
Answer» Correct option is (a) Ha(s)=\( \int_{-\INFTY}^{\infty} H(t)e^{-st} dt\) Easy explanation: We know that the impulse response h(t) and the LAPLACE TRANSFORM Ha(s) are RELATED by the equation. Ha(s)=\( \int_{-\infty}^{\infty} h(t)e^{-st} dt\).

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