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What is the relationship between Gibbs free energy of the cell reaction in a galvanic cell and the emf of the cell ? When will the maximum work be obtained froma galvanic cell ?

Answer»

Solution :If concentration of all reacting species is unity, then `E_("cell")=E_("Cell")^(@)` and `DeltaG^(@)=-nFE_("cell")^(@)`
where, `DeltaG_(r)G^(@)` is STAN dard GIBBS energy of the reaction
`E_("cell")^(@)=` emf of the cell
`nF=`charge PASSED
If we want to obtain m aximum WORK from a galvanic cell then charge has to be passed reversible.
The reversibly work done by a galvanic cell is equal to decrease in its Gibbs energy
`Delta_(r)G=-nFE_("cell")`
As `E_("cell")`is an intensive parameter but `Delta_(f)=G` is an EXTENSIVE thermodynamic property and thevalue depends on n.
For reaction, `Zn(s)+Cu^(2+)(aq)rarrZn^(2+)(aq)+Cu(s)` in a galvanic cell.
`Delta_(r)G=-2FE_("cell")` [Here,n=2]


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