1.

What is the shortest wavelength in Bracket series of He^(+) spectrum ?

Answer»

`(100)/(9R_(H))`
`(16)/(R_(H))`
`(25)/(R_(H))`
`(9)/(R_(H))`

Solution :Shortest wavelength of Bracket series is correspond to `oo rarr 4` transition `n_(1) = 4, n_(2) = oo`
`(1)/(lambda_("min")) = R_(H) XX 2^(2) ((1)/(4^(2)) - (1)/(oo^(2))) rArr lambda_("min") = (4)/(R_(H))`


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