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What is the shortest wavelength present in the Paschen series of spectral lines ? |
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Answer» Solution :Spectral LINES of Paschen series are given by the RELATION `(1)/(lambda) = R [(1)/(3^(2)) - (1)/(n^(2))]` For SHORTEST wavelength `n = oo` and we know that `R=1.097 xx 10^(7) m^(-1)` `therefore ""(1)/(lambda_("mix")) = 1.097 xx 10^(7) xx[(1)/(3) - (1)/(oo)] = 1.097 xx 10^(7) [(1)/(9)]` `rArr"" lambda_("mix") = (9)/(1.097 xx 10^(7)) = 8.20 xx 10^(-7) = 820nm` |
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