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what is the smallest fraction that must be added to 1 whole 1 upon 3 / 1 whole 1 upon 2 divided by 1 whole 1 upon 9 to make the result an integer |
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Answer» Answer: 1/5 Step-by-step explanation: let the fraction be X (1+1/3) => x + ------------ ÷ (1+1/9) (1+1/2) 4/3 => x+ -------- × 9/10 3/2 4×2×9 => x+ ------------ 3×3×10 4 => x+----- = integer (5/5) 5 => x = 5/5 -4/5 = 1/5 => smallest fraction = 1/5 hope this helps you |
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