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What is the speed of an apple dropped from a tree after 1.5 second? What distance will it cover during this time? Take g = 10 m/s2. |
Answer» An apple is dropped from a tree. ∴ Initial velocity u = 0 ; Time t = 1.5 s a = g = 10 m/s2 ; Final velocity v = ? v = u + at = 0 + 10 x 1.5 = 0 + 15 = 15 m/s Distance covered (s) = ut + 1/2 at2 = 0 × 1.5 + 1/2 × 10 × 1.5 × 1.5 = 0 + 5 × 2.25 = 11.25 m |
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