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What is the total number of factors of the number N = 411 × 145 × 112 ? |
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Answer» N = 411 × 145 × 112 = (22 )11 × (2 × 7)5 × 112 = 222 × 25 × 75 × 112 = 227 × 75 × 112 \(\therefore\) Total number of prime factors of N = (27 + 1) × (5 + 1) × (2 + 1) = 28 × 6 × 3 = 504. |
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