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What is the value of (1 + tan42°)(1 + tan3°)?1. 22. 13. 34. –2 |
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Answer» Correct Answer - Option 1 : 2 GIVEN: X = (1 + tan42°)(1 + tan3°) FORMULA: If A = B + C tan A = tan(B + C) = (tan B + tan C)/(1 – tan B tan C) ⇒ tan A = (tan B + tan C)/(1 – tan B tan C) ⇒ tan A – tan A tan B tan C = tan B + tan C ⇒ tan A = tan B + tan C + tan A tan B tan C CALCULATION: X = (1 + tan42°)(1 + tan3°) ⇒ X = 1 + tan42° + tan3° + tan42°tan3° ⇒ X = 1 + (tan42° + tan3° + tan42°tan3°) ⇒ X = 1 + (tan42° + tan3° + tan45°tan42°tan3°) ⇒ X = 1 + tan45° ⇒ X = 1 + 1 ⇒ X = 2 |
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