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What is the value of 273 K in degree Rankine?(a) 0^oR(b) 32^oR(c) 492^oR(d) 672^oRI have been asked this question in a national level competition.I'd like to ask this question from Temperature in division Temperature and Pressure of Basic Chemical Engineering

Answer» RIGHT option is (C) 492^oR

The best I can EXPLAIN: TR = (9/5)(273 – 273) + 492 = 492^oR.


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