1.

What is the value of `""^(8)C_(0)-""^(8)C_(1)+""^(8)C_(2)-""^(8)C_(3)+""^(8)C_(4)-""^(8)C_(5)+""^(8)C_(6)-""^(8)C_(7)+""^(8)C_(8)`

Answer» Correct Answer - A
`(1-x)^(n)=""^(n)C_(0)-""^(n)C_(1)(x)+""^(n)C_(2)x^(2)-""^(n)C_(3)x^(3)+...+(-1)^(n)""^(n)C_(n)`
Put x=1 and n=8
`therefore" "(1-1)^(8)=""^(8)C_(0)-""^(8)C_(1)+""^(8)C_(2)-""^(8)C_(3)+...+""^(8)C_(8)`
`rArr" "(""^(8)C_(0)-""^(8)C_(1)+""^(8)C_(3)+...+""^(8)C_(8))=0`


Discussion

No Comment Found