InterviewSolution
Saved Bookmarks
| 1. |
What is the value of `""^(8)C_(0)-""^(8)C_(1)+""^(8)C_(2)-""^(8)C_(3)+""^(8)C_(4)-""^(8)C_(5)+""^(8)C_(6)-""^(8)C_(7)+""^(8)C_(8)` |
|
Answer» Correct Answer - A `(1-x)^(n)=""^(n)C_(0)-""^(n)C_(1)(x)+""^(n)C_(2)x^(2)-""^(n)C_(3)x^(3)+...+(-1)^(n)""^(n)C_(n)` Put x=1 and n=8 `therefore" "(1-1)^(8)=""^(8)C_(0)-""^(8)C_(1)+""^(8)C_(2)-""^(8)C_(3)+...+""^(8)C_(8)` `rArr" "(""^(8)C_(0)-""^(8)C_(1)+""^(8)C_(3)+...+""^(8)C_(8))=0` |
|