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What is the value of β in a simplified CB configuration amplifier if IC = 124mA and IB = 1.26mA?(a) 98.41(b) 99.24(c) 100(d) 97.33I got this question by my college professor while I was bunking the class.I would like to ask this question from Simplified Calculations for the CB Configuration in section Low Frequency Transistor Amplifier Circuit of Electronic Devices & Circuits

Answer»

The correct option is (a) 98.41

Easiest explanation: The VALUE of β in a SIMPLIFIED common base amplifier CONFIGURATION can be calculated USING β = IC / IB. Given, IC = 124mA and IB = 1.26mA:

β = IC / IB = 124 / 1.26 = 98.41



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