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What is the value of k for which 2x2-kx+k=0 has equal roots? |
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Answer» Answer: Hello Mate . WassupStep-by-step explanation: The values of k = 4.Given:Quadratic equation 2x^{2}+Kx +2=02x2+Kx+2=0 has equal ROOTS.To find:The values of kExplanation:General format of quadratic equation is ax^2+bx+c =0ax2+bx+c=0 .If the roots of quadratic equation is equal then,\sqrt{B^{2} \ -\ 4ac }=0b2− 4ac=0Where,a = coefficient of x²b = coefficient of xc = constant term.\sqrt{b^{2} \ -\ 4ac }=0b2− 4ac=0b² - 4ac =0Comparing the quadratic equation2x^{2}+Kx +2=02x2+Kx+2=0b = k a=2 c=2k² - 4×2×2 = 0k² = 16k = \sqrt{16}16k = 4Hope It Helps You . If yes . Then PLEASE like , rate and mark as BRAINLIEST answer . |
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