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What is the value of k if \(\begin{vmatrix}y + z & x & x \\y & z + x & y \\z & z & x + y\end {vmatrix}\) ?(a) 4(b) -4(c) 1(d) 0I had been asked this question in an interview for job.Asked question is from Application of Determinants in portion Determinants of Mathematics – Class 12

Answer»

Correct ANSWER is (a) 4

Explanation: Put the VALUE of x, y, z = 1

Thus, putting the value of x = 1, y = 1 and z = 1 on both sides, we get

\(\BEGIN{vmatrix}2 & 1 & 1 \\1 & 2 & 1 \\1 & 1 & 2 \end {vmatrix}\) = k

So, solving the determinant we get k = 4.



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